{VERSION 5 0 "IBM INTEL NT" "5.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Times" 1 14 0 0 0 0 2 2 2 0 0 0 0 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Plot" 0 13 1 {CSTYLE "" -1 -1 " " 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 } {PSTYLE "Title" 0 18 1 {CSTYLE "" -1 -1 "" 1 18 0 0 0 0 0 1 1 0 0 0 0 0 0 1 }3 0 0 -1 12 12 0 0 0 0 0 0 19 0 }{PSTYLE "R3 Font 0" -1 256 1 {CSTYLE "" -1 -1 "Helvetica" 1 14 0 0 0 0 2 1 2 0 0 0 0 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "R3 Font 2" -1 257 1 {CSTYLE "" -1 -1 "Courier" 1 14 0 0 0 0 2 2 2 0 0 0 0 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 18 "" 0 "" {TEXT -1 17 "INVERSE FUNCTIONS" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "" 0 "" {TEXT -1 31 "IN VERSE TRIGONOMETRIC FUNCTIONS" }}{PARA 0 "" 0 "" {TEXT -1 17 "The sine function" }}{PARA 0 "" 0 "" {TEXT -1 51 " \+ f(x) = sin x " }}{PARA 0 "" 0 "" {TEXT -1 78 "oscillates bet ween -1 and 1 as x varies over the extent of any interval of" }} {PARA 0 "" 0 "" {TEXT -1 70 "length 2 Pi. This means that the sine fu nction does not have a unique" }}{PARA 0 "" 0 "" {TEXT -1 75 "inverse \+ function. Rather it has (infinitely) many inverses to (associated) " } }{PARA 0 "" 0 "" {TEXT -1 81 "functions defined over intervals in whic h the sine function is either increasing " }}{PARA 0 "" 0 "" {TEXT -1 53 "or decreasing. The sine function is increasing on the" }}{PARA 0 " " 0 "" {TEXT -1 79 "interval [-Pi/2,Pi/2] with range [-1,1]. In this case Maple V recognizes the " }}{PARA 0 "" 0 "" {TEXT -1 85 "inverse \+ to the sine function over the interval $[-Pi/2,Pi/2]$ as the arcsin fu nction." }}{PARA 0 "" 0 "" {TEXT -1 0 "" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 18 "solve(y=sin(x),x);" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#-%'arcsi nG6#%\"yG" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart;" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 39 "Let us evaluate this function at \+ x=-1." }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 11 "arcsin(-1);" }}{PARA 11 " " 1 "" {XPPMATH 20 "6#,$%#PiG#!\"\"\"\"#" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 86 "We plot the sine function, the identity, and the arcsine function on the same graph. " }}{PARA 0 "" 0 "" {TEXT -1 0 "" }} {PARA 0 "> " 0 "" {MPLTEXT 1 0 53 "plot(\{sin(x),arcsin(x)\},x=-Pi/2.. Pi/2,y=-Pi/2..Pi/2);" }}{PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "6&-%'CURVESG6$7S7$$!1++lBjzq:!#:$!\"\"\"\"!7$$!1NzQW&=B] \"F*$!1aD4FJcw**!#;7$$!142![ROFW\"F*$!13C*F37$$!1%4``jnW6\"F*$!1#>2jDjn(*) F37$$!1oW()o'>y/\"F*$!1GB9]HOj')F37$$!1WfpKW&Q\")*F3$!1(*GLjHo7$)F37$$ !1'e1Vw'\\I\"*F3$!13$zL\"zr8zF37$$!13*H!e\\fG&)F3$!1h'G5]X;`(F37$$!1`u @%3'*4&yF3$!1+!yURc*oqF37$$!1mnKC\\hqrF3$!1PT#\\TEfF3$!1(yNitD)zbF37$$!1-(RrNA:@&F3$!1&fQ.S( zy\\F37$$!1[5T-#\\F3$!1;:j*R[4'>F37$$!1SWU;s`+8F3$!197m2T(oH\"F37$$!1gSQF3$\"1&4S v&QH>>F37$$\"11j*\\(z-/EF3$\"1oO$\\!zpuDF37$$\"1#oMd]$=iKF3$\"16))*Q>J Y?$F37$$\"1H4XBG)*)*QF3$\"1l%fdLV4!QF37$$\"1DLY%*)Rgg%F3$\"1bi2AB*[W%F 37$$\"16;S?@OT_F3$\"1foz8Ol/]F37$$\"1MYS.Uq>fF3$\"1?'z@Ws*zbF37$$\"1\" oi?&HQMlF3$\"1(GhB%**>zgF37$$\"1r$zA=*Q1sF3$\"12;P(z[')f'F37$$\"1IJCuY pQyF3$\"1]!e4/]-1(F37$$\"1'G\"*Q5O'*\\)F3$\"1L,8\")Qc7vF37$$\"1inYgr#e 9*F3$\"1!)Qd?13BzF37$$\"1E5$3JHB#)*F3$\"1\"fd*>4R<$)F37$$\"1h>eG\")QZ5 F*$\"1\\j\\nn?h')F37$$\"1K#)fG(=S6\"F*$\"14O')>Uyu*)F37$$\"10`g$f(4!= \"F*$\"16rJQ=VY#*F37$$\"1n8'y?<3C\"F*$\"1a:'o4\"\\g%*F37$$\"1nP+Q(3/J \"F*$\"1mn3SE!Hm*F37$$\"1%yp@B_EP\"F*$\"1urX7gL/)*F37$$\"1OK@zn,R9F*$ \"1l,yOjH8**F37$$\"1<#f'=h`-:F*$\"14edku_>fF3$!14l?,`z MjF37$$!1+++gB_6_F3$!1\">'>`Y+#[&F37$$!1++++#\\N$fLF37$$!1+++?5%*=EF 3$!19tA`G%)\\EF37$$!1+++I%QP(>F3$!1J:S,My')>F37$$!1+++?s`+8F3$!1Bg#ohJ UI\"F37$$!1,+++NGBoFjr$!1Dpis\"*eGoFjr7$$!1++++ql]:F`s$!1igV@wl]:F`s7$ $\"1++++&Q8x'Fjr$\"1@$4FvBlx'Fjr7$$\"1+++q$z+G\"F3$\"1C7j08g$G\"F37$$ \"1+++]qFJ>F3$\"1MO\\1()[V>F37$$\"1+++qz-/EF3$\"1XOz%p$RMEF37$$\"1+++5 N=iKF3$\"1!oan+.IK$F37$$\"1+++?G)*)*QF3$\"1g?#3I6_+%F37$$\"1+++!*)Rgg% F3$\"1\\:x$[bny%F37$$\"1+++?@OT_F3$\"10)*)HD0q^&F37$$\"1++++Uq>fF3$\"1 _]nTY,NjF37$$\"1******\\HQMlF3$\"17B'40x67(F37$$\"1+++!=*Q1sF3$\"1PxAZ UBZ!)F37$$\"1+++qYpQyF3$\"1w#))p1L(3!*F37$$\"1++++hj*\\)F3$\"1\"RXz@;f ,\"F*7$$\"1+++gr#e9*F3$\"15#*G^[Za6F*7$$\"1+++5$HB#)*F3$\"1T+z)46?Q\"F *7$%%FAILGFeel-F\\[l6&F^[lF-F_[lF--%+AXESLABELSG6$Q\"x6\"Q\"yF\\fl-%%V IEWG6$;$!+Fjzq:!\"*$\"+Fjzq:FdflFafl" 1 2 0 1 10 0 2 9 1 4 2 1.000000 45.000000 45.000000 0 0 "Curve 1" "Curve 2" }}}}{EXCHG {PARA 13 "" 1 " " {TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 78 "Exercise 1. 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Find the inverse functions for each the following function AND graph the original function and t he respective inverse function together." }}{PARA 0 "" 0 "" {TEXT -1 16 "(a) f1(x) = 2^x;" }}{PARA 0 "" 0 "" {TEXT -1 60 "(b) f2(x) = log[5 ](x) (this is a log function with base 5];" }}{PARA 0 "" 0 "" {TEXT -1 26 "(c) f3(x) = 3*(x-4)^(1/3)." }}}}{MARK "5 0 0" 0 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }